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Re: John!!!


  • From: P3D William Carter <wc@xxxxxxxxxxxxxxxxxxx>
  • Subject: Re: John!!!
  • Date: Mon, 14 Oct 1996 13:09:52 -0700

John B asks:
>Would you please describe the tests, their methodology, and give 
>their results?

And:
>Can you tell us how the Rayleigh Criterion applies to binocular 
>vision?  (I can see how it would apply to monocular vision.)

I'll try "And" first, to see where it goes. 
Let's put "binocular vision" on hold. Think of that as a display technology  for 
now.
I really want to get the root idea of a single-lens-as-range-finder across. I 
think Rayleigh, De Broglie, Daws, acoustic waves etc., all apply here... 
Resolution is the heart of it.

As you know, some point not at the "object plane", will be projected in part as 
the aperture onto the plane of focus. This is generally refered to as being "out 
of focus" o-) 
The further an object is from this object plane ("O" is farther than "o") , the 
greater it's diameter... Not!
Some shifts along this Z-axis may be to small to be resolved.  What is that 
distance? What sort of depth resolution can we expect? How does that 
compare to more well known systems?

Bull, if "flatties" have depth info, how come the're not "3-D"?!
One reason flatties are 2-D is because a background "O", "o", or "." looks just 
like a foreground "O", "o", or ".". A difference between the two can be made by 
encoding the lens aperture. 
Since the cone of light from a lens is a projection of the aperture of that lens 
by some object point, and since this cone reverses at the focal point, so will 
the encoded aperture reverse the encoding elements at that point. 
For example, we can bisect the aperture with red/left and cyan/right filters. 
Now, as long as an object point is in the forground, it will be projecting the 
aperture "o" as red on the left and cyan on the right. If it's in the background, 
it will have come to a point and reversed it's self so that now it appears as 
cyan on the left and red on the right.

Well, I see I've wandered. And it's nap time! 
I'll have to come back to it.







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