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RE: Lenticular (Call to Nimstec)
- From: P3D <GCCampos@xxxxxxx>
- Subject: RE: Lenticular (Call to Nimstec)
- Date: Sat, 1 Feb 1997 20:35:42 -0500 (EST)
Well, I called Nimstec in Duluth, GA and asked about the spacing
between shots. He sounded about 90% confident with his information.
He said that in a four picture lent one would see adjacent images, and
that in an eight picture lent one would see every other picture. He didn't
provide any equations, but did say that when he sets up an eight picture
shot, he makes less than a quarter inch movement between the
foreground and background (on film deviation?) as seen in the viewfinder,
between the leftmost and rightmost frame. This makes sense: if you see
every other picture, that would make the maximum on film deviation for
each stereo piar you see 1.8 mm (.25 inch X 25.4 mm) X (2 / 7). 1.8 mm
is more than the more common value (Ferwerda's?) 1.7 mm but it's close
enough to confirm the "every other picture" statement. One way to know
for sure would be by taking an eight frame shot and placing a different
number label in each frame.
Elliot, did I understand that you have an Imagetrac that will set
up the shot for you? Try setting up one for eight frames with,
"f" = 50mm lens,
("d" = 50/30) 35mm film,
closest object "an" = 1 foot,
farthest object "af" = 1.5 foot,
focused at "a" = 1.2 feet (2 * an * af / (an + af)).
Using the modified Spicer/Bercovitz equation:
B0 = ((f * an * 304.8 * af ) * (1/f - 1/ (a * 304.8)) / (30 * (af -an)),
B0, the distance between shots, would then be 26 mm or about one inch.
If this is close to usefull, and the "every other frame" is correct, then
the distance from frame one to frame eight would be a close to 92 mm.
(26.3133 * 7/2). If it's every third, then the total distance would be
closer to 61.4 mm.
What did you get?
Grant Campos
Should we continue this thread on Tech-3D alone?
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