P3D Boris reveals answers!!

[bercov@xxxxxxxxxxx (John Bercovitz)]

In a private message, Boris has revealed the correct answers!
He took the pix with a 50 mm lens and the camera to subject 
distance was 850 mm.  Since 850 >> 50, we can say that the 
image-side perspective point is about 53 mm (from the Gaussian 
lens formula) from the negative.  Furthermore, Boris cropped 
the image so that he used about 20 mm of the negative for the 
top row of pictures.  Now we've got it!  You must view the top 
row of pictures from a distance equal to 53/20 = 2.65 times the 
image width as seen on your screen.  So if the image width is 
80 mm on DokTee's screen, DokTee must view from a distance of 
210 mm (8.3") to avoid the stretch he was protesting about.  
Fortunately, DokTee is still a young man and can do that.  8-)  
Some of us, those of us with only three prescriptions in our specs....

Moving down one row, the images are 3X enlargements of the 
images in the top row.  So the new viewing distance is 
3 X 2.65 = 8.  So if the images are 80 mm wide on DokTee's screen, 
DokTee must view from a distance of 640 mm (25") to avoid stretch
or squash.  Even I can do that!  8-)  Now, how many of you posted 
that the images looked right to you from 25"?  Most everyone, as 
I recall it.  ;-)

John B


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